Решите уравнение: \(\frac{cosx}{1+sinx}=0.\)
\(\frac{\pi}{2}+{2\pi}k,k{\in}Z\)
\(\frac{\pi}{2}+{\pi}k,k{\in}Z\)
\(\frac{\pi}{3}+{2\pi}k,k{\in}Z\)
\(\frac{\pi}{6}+{2\pi}k,k{\in}Z\)