Решите систему уравнений:

\(\displaystyle\begin{aligned}\begin{cases}\dfrac{2x+3}{7}+\dfrac{4y+3}{3}=\dfrac{1}{3}{\small,}\\ \\\dfrac{3x-3}{2}+\dfrac{y+4}{4}=5{\small.}\end{cases}\end{aligned}\)

\(\displaystyle x=\) [ ] \(\displaystyle ;\)\(\displaystyle y=\)[ ]\(\displaystyle .\)