Решите систему уравнений \(\begin{cases}-2(a - b)+16 = 3(b+7), \\ 6a -(a-5) =-8-(b+1). \end{cases}\)
a = –3, b = 1.
a = –3, b = –1.
a = 3, b = –1.
a = 3, b = 1.