Решите неравенство методом интервалов: \( \left( x- \frac{1}{3} \right) \left(x-\frac{1}{8} \right) \geqslant 0{ .}\) \( x \in \left[ \frac{1}{8};\frac{1}{3} \right] \) \( x \in \left( -\infty;\frac{1}{8}\right] \cup \left[ \frac{1}{3};+ \infty \right) \) \( x \in \left(\frac{1}{7};\frac{1}{3}\right) \) \( x \in \left( -\infty;\frac{1}{8}\right) \cup \left( \frac{1}{3};+ \infty \right) \)

Задание

Решите неравенство методом интервалов:

\(\displaystyle \left( x- \frac{1}{3} \right) \left(x-\frac{1}{8} \right) \geqslant 0{\small .}\)

\(\displaystyle x \in \left[ \frac{1}{8};\frac{1}{3} \right] \)
\(\displaystyle x \in \left( -\infty;\frac{1}{8}\right] \cup \left[ \frac{1}{3};+ \infty \right) \)
\(\displaystyle x \in \left(\frac{1}{7};\frac{1}{3}\right) \)
\(\displaystyle x \in \left( -\infty;\frac{1}{8}\right) \cup \left( \frac{1}{3};+ \infty \right) \)