Задание

Решите неравенство \(\dfrac{2\log_2 (256x)-41}{\log_2^2 x-\log_2 x^8} \leqslant 1.\)

\(x \in \left( 0; 1\right) \cup \left(256; +\infty\right)\)

\(x \in \left( 0; 1\right) \cup \left\{32\right\} \cup \left(256; +\infty\right)\)

\(x \in \left( 0; 1\right] \cup \left\{32\right\} \cup \left[256; +\infty\right)\)

\(x \in \left[ 0; 1\right] \cup \left(256; +\infty\right)\)