Задание
Решите неравенство
\[\frac{x^2}{5}+\frac{2x}{3}\ge\frac{8}{15}\]
- \[(-\infty;-4]\cup[\frac{2}{3};\infty)\]
- \[(-\infty;-4)\cup(\frac{2}{3};\infty)\]
- \[[-4;\frac{2}{3}]\]
- \[(-4;\frac{2}{3})\]