Задание
Решите неравенство \(\frac{(6x+2)(x-7)(x+3)}{(2x-8)(6-x)} \geqslant 0.\)
- \({(-\infty; -3] \cup \left[-\dfrac13; 4\right) \cup (6; 7]}\)
- \({(-\infty; -3] \cup \left[-\dfrac13; 4\right) \cup [6; 7]}\)
- \([-3; -2] \cup (4; 6) \cup [7; +\infty)\)
- \([-3; -2] \cup [4; 6] \cup [7; +\infty)\)
- \((-\infty; -6) \cup [-3; -2] \cup (4; 7]\)
- \((-\infty; -6] \cup [-3; -2] \cup [4; 7]\)