Решите неравенство \(\displaystyle lo{{g}_{12{{x}^{2}}-41x+35}}\left( 3-x \right)\le lo{{g}_{2{{x}^{2}}-5x+3}}\left( 3-x \right).\) \(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right]\) \(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right)\) \(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\) \(\displaystyle x\in \mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right]\)

Задание

Решите неравенство \(\displaystyle lo{{g}_{12{{x}^{2}}-41x+35}}\left( 3-x \right)\le lo{{g}_{2{{x}^{2}}-5x+3}}\left( 3-x \right).\)

\(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right]\)
\(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right)\)
\(\displaystyle x\in \left( -\infty;\frac{1}{2}\right)\)
\(\displaystyle x\in \mathop{\cup }^{}\left(\frac{3}{2}; \frac{8}{5}\right]\)