Решите неравенство \(2^{x^{2}}\le(\frac{1}{2})^{2x-3}.\) \(x\in[-1;3]\) \(x\in[-1;+\infty)\) \(x\in(-\infty;-3]\cup[1;+\infty)\) \(x\in[-3;1]\) \(x\in(-\infty;-1]\cup[3;+\infty)\) \(x\in(-\infty;-3]\)

Задание

Решите неравенство \(2^{x^{2}}\le(\frac{1}{2})^{2x-3}.\)

\(x\in[-1;3]\)
\(x\in[-1;+\infty)\)
\(x\in(-\infty;-3]\cup[1;+\infty)\)
\(x\in[-3;1]\)
\(x\in(-\infty;-1]\cup[3;+\infty)\)
\(x\in(-\infty;-3]\)