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Реши уравнение \({\sin 3x = -\dfrac{1}{2}}\) .

Ответ:

• \(\cfrac{2\pi k}{3}\)
• \(-\cfrac{\pi}{18}\)
• \(\cfrac{5\pi}{4}\)
• \(\cfrac{7\pi}{18}\)
• \(\pi k\)
• \(-\cfrac{\pi}{3}\)
• \(\pi n\)
• \(\cfrac{2\pi n}{3}\)

[ ] \(+\) [ ], \(n\in\Z;\)

[ ] \(+\) [ ], \(k\in\Z.\)