Задание
Реши уравнение \((6\sin x - 6)\)\(\left(\operatorname{tg} x - \frac{1}{\sqrt{3}}\right)\) \(=\) \(0\):
- \(x = \frac{\pi}{6} + 2\pi n \; ; \; x = \frac{\pi}{2} + 2\pi n\)
- \(x = \frac{\pi}{6} + \pi n; x = \frac{\pi}{2} + 2\pi n\)
- \(x = \frac{\pi}{3} + \pi n\)
- \(x = \frac{\pi}{6} + \pi n\)