Задание
Реши тригонометрическое уравнение
\(\sin x+\sin2x+\cos x=1\)
- \(\left[\begin{aligned} &x=2\pi n,\space n\in\mathbb{Z}\\ &x=\dfrac{\pi}4+2\pi m,\space m\in\mathbb{Z}\end{aligned}\right.\)
- \(\left[\begin{aligned} &x=2\pi n,\space n\in\mathbb{Z}\\ &x=\dfrac{\pi}2+2\pi m,\space m\in\mathbb{Z}\end{aligned}\right.\)
- \(\left[\begin{aligned} &x=4\pi n,\space n\in\mathbb{Z}\\ &x=\dfrac{\pi}2+2\pi m,\space m\in\mathbb{Z}\end{aligned}\right.\)
- \(\left[\begin{aligned} &x=2\pi n,\space n\in\mathbb{Z}\\ &x=-\dfrac{\pi}2+2\pi m,\space m\in\mathbb{Z}\end{aligned}\right.\)