Реши тригонометрическое уравнение

\(\dfrac{\tg 3x-\tg 4x}{1+\tg 3x\tg 4x}=1\)

• \(\dfrac{\pi}4\)
• \(-\dfrac{\pi}4\)
• \(\dfrac{\pi}2\)
• \(-\dfrac{\pi}2\)
• \(\dfrac{\pi n}2\)
• \(\pi n\)
• \(2\pi n\)

Ответ:[ ] \(+\) [ ] \(, n\in\Z.\)