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Реши неравенство \((x+1)\log\_2 12 + \log\_2\left(3^x - \dfrac{1}{12}\right) \leq 2x - 1\) .

• \(x \in \left(\log\_3 \dfrac{1}{12}; \log\_3 \dfrac{1}{4}\right)\)
• \(x \in \left(\log\_3 \dfrac{1}{12}; \log\_3 \dfrac{1}{4}\right]\)
• \(x \in \left[\log\_3 \dfrac{1}{12}; \log\_3 \dfrac{1}{4}\right]\)
• \(x \in \left(0; \log\_3 \dfrac{1}{4}\right]\)