Реши неравенство методом интервалов: ${\left(x + \dfrac{1}{3}\right)\left(x - \dfrac{2}{5}\right) \geq 0}$. $\left(-\infty;-\dfrac{2}{5}\right)\cup\left(\dfrac{1}{3};+\infty\right)$ $\left(-\infty;-\dfrac{2}{5}\right]\cup\left[\dfrac{1}{3};+\infty\right)$ $\left(-\infty;-\dfrac{1}{3}\right]\cup\left[\dfrac{2}{5};+\infty\right)$ $\left(-\infty;-\dfrac{1}{3}\right)\cup\left(\dfrac{2}{5};+\infty\right)$

Задание

Реши неравенство методом интервалов:

\({\left(x + \dfrac{1}{3}\right)\left(x - \dfrac{2}{5}\right) \geq 0}\).

Выбери верный вариант.

\(\left(-\infty;-\dfrac{2}{5}\right)\cup\left(\dfrac{1}{3};+\infty\right)\)
\(\left(-\infty;-\dfrac{2}{5}\right]\cup\left[\dfrac{1}{3};+\infty\right)\)
\(\left(-\infty;-\dfrac{1}{3}\right]\cup\left[\dfrac{2}{5};+\infty\right)\)
\(\left(-\infty;-\dfrac{1}{3}\right)\cup\left(\dfrac{2}{5};+\infty\right)\)