Реши неравенство методом интервалов

\(\cfrac{2x^2-2x+1}{2x-1}\leqslant 1\)

• \(x \in \left(-\infty; \cfrac12\right) \cup \{1\}\)
• \(x \in \left(-\infty; \cfrac12\right) \)
• \(x \in \left(-\infty; \cfrac12\right] \)
• \( x \in \left(\cfrac12 ; +\infty\right)\)