Разложи на множители. 9а^2-25=(3а)^2-5^2=(3a-5)( ). -y^6+\dfrac{1}{25}x^2=\dfrac{1}{25}x^2-y^6=\left(\dfrac{1}{5}x\right)^2-(y^3)^2= . a^4-0,04b^8=( )^2-( )^2= . \dfrac{9}{16}x^2y^4-1= .

Задание

Заполни пропуски

Разложи на множители.

\(9а^2-25=(3а)^2-5^2=(3a-5)(\) [ ] \()\) .
\(-y^6+\dfrac{1}{25}x^2=\dfrac{1}{25}x^2-y^6=\left(\dfrac{1}{5}x\right)^2-(y^3)^2=\) [ ].
\(a^4-0,04b^8=(\) [ ] \()^2-(\) [ ] \()^2=\) [ ].
\(\dfrac{9}{16}x^2y^4-1=\) [ ].