\raisebox{-0.8em}{$ 1)\kern{0.7em} 3^2\cdot a^3\cdot 3\cdot a^3\cdot (2x)^7:(2x)^5= $} \newline \raisebox{-0.8em}{$ =(3a^2) $} \raisebox{-0.8em}{$ +(2x) $} \raisebox{-0.8em}{$ ; $} \raisebox{-0.8em}{$ 2)\kern{0.7em} (b^3)^3-(a+b)^8:(a+b)^3= $} \newline \raisebox{-0.8em}{$ =b $} \raisebox{-0.8em}{$ -(a+b) $} \raisebox{-0.8em}{$ ; $} \raisebox{-0.8em}{$ 3)\kern{0.7em} (x^3)^5\cdot y\cdot y^3\cdot y^5+(a^2)^4\cdot b^8:b^3:b^2= $} \newline \raisebox{-0.8em}{$ =x $} \raisebox{-0.8em}{$ \cdot y $} \raisebox{-0.8em}{$ +a $} \raisebox{-0.8em}{$ \cdot b $} \raisebox{-0.8em}{$ ; $} \raisebox{-0.8em}{$ 4)\kern{0.7em} 3 \cdot m^2 \cdot m^3 \cdot m^4 \cdot n^{13}:n^7 - $} \raisebox{-0.8em}{$ 2\cdot n\cdot n^2\cdot n^3\cdot m^{14}:m^5= $} \newline \raisebox{-0.8em}{$ =m $} \raisebox{-0.8em}{$ \cdot n $} \raisebox{-0.8em}{$ . $}
Задание

Заполни пропуски

\(\raisebox{-0.8em}{\)1)\kern{0.7em} 32\cdot a3\cdot 3\cdot a^3\cdot (2x)^7:(2x)5=\(}\) \(\newline\) \(\raisebox{-0.8em}{\)=(3a2)\(}\) [ ] \(\raisebox{-0.8em}{\)+(2x)\(}\) [ ] \(\raisebox{-0.8em}{\);\(}\)

\(\raisebox{-0.8em}{\) 2)\kern{0.7em} (b^3)^3-(a+b)^8:(a+b)^3=\(}\) \(\newline\) \(\raisebox{-0.8em}{\)=b\(}\) [ ] \(\raisebox{-0.8em}{\)-(a+b)\(}\) [ ] \(\raisebox{-0.8em}{\);\(}\)

\(\raisebox{-0.8em}{\)3)\kern{0.7em} (x3)5\cdot y\cdot y3\cdot y5+(a2)4\cdot b8:b3:b^2=\(}\) \(\newline\) \(\raisebox{-0.8em}{\)=x\(}\) [ ] \(\raisebox{-0.8em}{\)\cdot y\(}\) [ ] \(\raisebox{-0.8em}{\)+a\(}\) [ ] \(\raisebox{-0.8em}{\)\cdot b\(}\) [ ] \(\raisebox{-0.8em}{\);\(}\)

\(\raisebox{-0.8em}{\)4)\kern{0.7em} 3 \cdot m2 \cdot m3 \cdot m4 \cdot n{13}:n7 -\(}\) \(\raisebox{-0.8em}{\)2\cdot n\cdot n2\cdot n3\cdot m{14}:m^5= \(}\) \(\newline\) \(\raisebox{-0.8em}{\)=m\(}\) [ ] \(\raisebox{-0.8em}{\)\cdot n\(}\) [ ] \(\raisebox{-0.8em}{\).\(}\)