Задание

Приведи дроби \(\frac{5u}{v}\), \(\frac{u}{u-v}\) и \(\frac{1}{u+v}\) к общему знаменателю.

Выбери правильный вариант (варианты) ответа:

  • \(\frac{5u^3 - 5uv^2}{v(u^2 - v^2)}, \frac{vu^2 - uv^2}{v(u^2 - v^2)} \text{ и } \frac{vu + v^2}{v(u^2 - v^2)}\)
  • \(\frac{5u^3 - 5uv^2}{v(u-v)(u+v)}, \, \frac{vu^2 + uv^2}{v(u-v)(u+v)} \,\,\text{и}\, \frac{vu - v^2}{v(u-v)(u+v)}\)
  • \(\frac{5u^3 - 5uv^2}{v(u-v)(u+v)}, \frac{vu^2 - uv^2}{v(u-v)(u+v)} \text{ и } \frac{vu + v^2}{v(u-v)(u+v)}\)
  • \(\frac{5u^3 - 5uv^2}{u^2 - v^2}, \, \frac{vu - v^2}{u^2 - v^2} \,\,\text{и}\, \frac{u+v}{u^2 - v^2}\)
  • \(\frac{5u^3 - 5uv^2}{u^2 - v^2}, \, \frac{vu + v^2}{u^2 - v^2} \,\text{и}\, \frac{u - v}{u^2 - v^2}\)
  • \(\frac{5u^3 - 5uv^2}{v(u^2 - v^2)}, \frac{vu^2 + uv^2}{v(u^2 - v^2)} \text{ и } \frac{vu - v^2}{v(u^2 - v^2)}\)
  • другой ответ