Задание

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а) \(2\cfrac{3}{4}+\left(-4\cfrac{5}{8}\right)=2\cfrac{6}{8}+\left(-4\cfrac{5}{8}\right)=-\left(4\cfrac{5}{8}-2\cfrac{6}{8}\right)=-\left(3+\cfrac{13}{8}-2\cfrac{6}{8}\right)=-1\cfrac{7}{8}\) ;

б) \(-6\cfrac{20}{21}-\left(-2\cfrac{3}{7}\right)=-6\cfrac{20}{21}-\left(-2\cfrac{9}{21}\right)=-6\cfrac{20}{21}+2\cfrac{9}{21}=-\left(6\cfrac{20}{21}-2\cfrac{9}{21}\right)=-4\cfrac{11}{21}\) ;

в) \(5\cfrac{2}{13} - 8\cfrac{1}{26} = 5\cfrac{4}{26} - 8\cfrac{1}{26} = -\left(8\cfrac{1}{26} - 5\cfrac{4}{26}\right) = -\left(7 + \cfrac{27}{26} - 5\cfrac{4}{26}\right) = -2\cfrac{23}{26}\) ;

г) \(5\cfrac{4}{15} + 8\cfrac{1}{3} =\) [ ];

д) \(-6\cfrac{2}{7} - 3\cfrac{3}{14} =\) [ ];

е) \(4\cfrac{10}{11} - \left(-1\cfrac{1}{22}\right) =\) [ ];

ж) \(4\cfrac{11}{12} - 7\cfrac{13}{18} =\) [ ].