Основано на упр. 49 стр. 26

Реши задачу

В трапеции \(ABCD\) углы \(A\) и \(D\) равны \(50\degree\) .

Найди углы между векторами:

a) \(\overrightarrow{AB}\) и \(\overrightarrow{AD}\) ; б) \(\overrightarrow{AD}\) и \(\overrightarrow{DC}\) ; в) \(\overrightarrow{AB}\) и \(\overrightarrow{CD}\) ; г) \(\overrightarrow{BA}\) и \(\overrightarrow{CD}\) ; д) \(\overrightarrow{BC}\) и \(\overrightarrow{DA}\) ; е) \(\overrightarrow{AD}\) и \(\overrightarrow{BC}\) .

Ответ:

a) \(\widehat{\overrightarrow{AB}\overrightarrow{AD}} = 50\degree\)

б) \(\widehat{\overrightarrow{AD}\overrightarrow{DC}} = \) [ ] \(\degree\)

в) \(\widehat{\overrightarrow{AB}\overrightarrow{CD}} = \) [ ] \(\degree\)

г) \(\widehat{\overrightarrow{BA}\overrightarrow{CD}} = \) [ ] \(\degree\)

д) \(\widehat{\overrightarrow{BC}\overrightarrow{DA}} = \) [ ] \(\degree\)

е) \(\widehat{\overrightarrow{AD}\overrightarrow{BC}} = \) [ ] \(\degree\)