Найди корни уравнения

\(\arctan(4x+1) = \frac{7\pi}{12}\).

Ответ:

• \(x = \frac{1}{4} \cdot \operatorname{tg} \frac{7\pi}{12} - \frac{1}{4}\)
• \(x = \left( \arctan{\frac{7\pi}{12}} - 1 \right) \div 4\)
• \(x = \frac{\frac{7\pi}{12} - 1}{4}\)