На стороне \(\displaystyle AD\) параллелограмма \(\displaystyle ABCD\) отмечена точка \(\displaystyle E\) так, что \(\displaystyle AB=AE{\small,}\) \(\displaystyle \angle BEA=70^{\circ}{\small.}\)

Найдите углы параллелограмма.

\(\displaystyle \angle A=\) [ ]\(\displaystyle ^{\circ}{\small;}\)   \(\displaystyle \angle B=\) [ ]\(\displaystyle ^{\circ}{\small;}\)   \(\displaystyle \angle C=\) [ ]\(\displaystyle ^{\circ}{\small;}\)   \(\displaystyle \angle D=\) [ ]\(\displaystyle ^{\circ}{\small.}\)