Из множеств \(A\) \(=\) \(\{1, 4, 7, 9\}\), \(B\) \(=\) \(\{4, 9, 15\}\), \(C\) \(=\) \(\{9, 17, -1\}\) получили множество \(D\) \(=\) \((A \cap B) \cup C\).

Заполни пропуски в порядке возрастания элементов.

Ответ:

\(1\) способ: \(D\) \(=\) \((A \cap B) \cup C\) \(=\) \(\{\)[ ], [ ]\(\}\)\(\cup\)\(\{9, 17, -1\}\) \(=\) \(\{\)[ ], [ ], [ ], [ ]\(\}\).

\(2\) способ: \(D\) \(=\) \((A \cap B) \cup C\) \(=\) \((A \cup C) \cap (B \cup C)\) \(=\) \(\{\)[ ], [ ], [ ], [ ], [ ], [ ]\(\}\)\(\bigcap\)\(\{\)[ ], [ ], [ ], [ ], [ ]\(\}\) \(=\) \(\{\)[ ], [ ], [ ], [ ]\(\}\).