Из множеств \(A =\) \(\{1, 4, 7, 10\}\), \(B =\) \(\{7, 12, 16\}\), \(C =\) \(\{4, 12, 16, -2\}\) получили множество \(D =\) \((B \cup C) \cap A\). Заполни пропуски в порядке возрастания элементов.

Ответ:

\(1\) способ: \(D =\) \((B \cup C) \cap A\) \(=\) \(\left\{\right.\)-2, 4, 7, 12, 16\(\}\)\(\bigcap\)\(\{1, 4, 7, 10\}\) \(=\) \(\left\{\right.\)4, 7\(\}\).

\(2\) способ: \(D =\) \((B \cup C) \cap A = (B \cap A) \cup (C \cap A)\) \(=\) \(\left\{\right.\)7\(\}\)\(\cup\)\(\left\{\right.\)4\(\}\) \(=\) \(\left\{\right.\)4, 7\(\}\).