Из множеств \(A\) \(=\) \(\{1, 3, 6, 10\}\), \(B\) \(=\) \(\{3, 10, 12\}\), \(C\) \(=\) \(\{10, 18, -3\}\) получили множество \(D\) \(=\) \((A \cap B) \cup C\).

Заполни пропуски в порядке возрастания элементов.

Ответ:

\(1\) способ: \(D\) \(=\) \((A \cap B) \cup C\) \(=\) \(\{\)[ ], [ ]\(\}\)\(\cup\)\(\{10, 18, -3\}\) \(=\) \(\{\)[ ], [ ], [ ], [ ]\(\}\).

\(2\) способ: \(D\) \(=\) \((A \cap B) \cup C\) \(=\) \((A \cup C) \cap (B \cup C)\) \(=\) \(\{\)[ ], [ ], [ ], [ ], [ ], [ ]\(\}\)\(\bigcap\)\(\{\)[ ], [ ], [ ], [ ], [ ]\(\}\) \(=\) \(\{\)[ ], [ ], [ ], [ ]\(\}\).