1) BE→+EG→=i→; 2) FB→−FC→=i→; 3) FG→+GC→+CE→=i→; 4) CA→−GA→−EG→=i→.

Задание

\(\overrightarrow{BE} + \overrightarrow{EG} = \overrightarrow{\square}\);
\(\overrightarrow{FB} - \overrightarrow{FC} = \overrightarrow{\phantom{BC}}\);
\(\overrightarrow{FG} + \overrightarrow{GC} + \overrightarrow{CE} = \overrightarrow{\square}\);
\(\overrightarrow{CA} - \overrightarrow{GA} - \overrightarrow{EG} = \overrightarrow{\square}\).