1) CB→+BF→=i→; 2) GD→−GA→=i→; 3) FG→+GC→+CE→=i→; 4) AD→−GD→−FG→=i→.

Задание

\(\overrightarrow{CB} + \overrightarrow{BF} = \overrightarrow{\square}\);
\(\overrightarrow{GD} - \overrightarrow{GA} = \overrightarrow{\square}\);
\(\overrightarrow{FG} + \overrightarrow{GC} + \overrightarrow{CE} = \overrightarrow{\square}\);
\(\overrightarrow{AD} - \overrightarrow{GD} - \overrightarrow{FG} = \overrightarrow{\square}\).