Here is the cross section of a rubber ball of outside diameter 22 cm. The thickness of the rubber is 0.5 cm. What is the area of the inside surface of the ball to the nearest \(cm^2?\) \(1,385 cm^2\) \(1,452 cm^2\) \(1,521 cm^2\) \(4,849 cm^2\)
Задание

Here is the cross section of a rubber ball of outside diameter 22 cm. The thickness of the rubber is 0.5 cm.
What is the area of the inside surface of the ball to the nearest \(cm^2?\)

  • \(1,385 cm^2\)
  • \(1,452 cm^2\)
  • \(1,521 cm^2\)
  • \(4,849 cm^2\)