Задание
Here is the cross section of a rubber ball of outside diameter 22 cm. The thickness of the rubber is 0.5 cm.
What is the area of the inside surface of the ball to the nearest \(cm^2?\)
- \(1,385 cm^2\)
- \(1,452 cm^2\)
- \(1,521 cm^2\)
- \(4,849 cm^2\)