\(\frac{7}{16}\) - 0,12 = \(\frac{127}{400}\) \(\frac{19}{116}\) \(\frac{5}{12}\)
Задание

\(\frac{7}{16}\) - 0,12 =

  • \(\frac{127}{400}\)
  • \(\frac{19}{116}\)
  • \(\frac{5}{12}\)