\[\frac{3x^3-12x^2-6x+24}{x^2-16}=0.\] \[\sqrt{2}\] \[-\sqrt{2}\] 4 -4 2 -2
Задание

Решите уравнение

\[\frac{3x^3-12x^2-6x+24}{x^2-16}=0.\]

  • \[\sqrt{2}\]

  • \[-\sqrt{2}\]

  • 4

  • -4

  • 2

  • -2