Дополните правильные варианты группировки слагаемых и разложите на множители в произведение двучлена и трехчлена:

\(\displaystyle \color{red}{3z^{\,12}}+72z^{\,7}+\color{red}{9z^{\, 3}}+\color{blue}{27z^{\,9}}+8z^{\,10}+\color{blue}{81}=\)

\(\displaystyle =(\color{red}{3z^{\,12}}+\)[ ]\(\displaystyle +\color{red}{9z^{\, 3}})+(\color{blue}{27z^{\,9}}+\)[ ]\(\displaystyle +\color{blue}{81})=\)

\(\displaystyle =\big(\)[ ]\(\displaystyle \big)\big(\)[ ]\(\displaystyle \big)\)