\dfrac3{(2^{2-x^2}-1)^2}-\dfrac4{2^{2-x^2}-1}+1\ge0 (-\infty;-\sqrt2)\cup(-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2) (-\infty;-\sqrt2)\cup(-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2)\cup(\sqrt2;+\infty) (-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2)\cup(\sqrt2;+\infty) (-\infty;-\sqrt2)\cup[1;\sqrt2)\cup(\sqrt2;+\infty)

Задание

Реши неравенство

\(\dfrac3{(2^{2-x^2}-1)^2}-\dfrac4{2^{2-x^2}-1}+1\ge0\)

\((-\infty;-\sqrt2)\cup(-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2)\)
\((-\infty;-\sqrt2)\cup(-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2)\cup(\sqrt2;+\infty)\)
\((-\sqrt2;-1]\cup\{0\}\cup[1;\sqrt2)\cup(\sqrt2;+\infty)\)
\((-\infty;-\sqrt2)\cup[1;\sqrt2)\cup(\sqrt2;+\infty)\)