Дано:

\(ABCD\) — параллелограмм;

\(\angle\) \(BCA =\) 37\(\degree\);

\(\angle\) \(BAC =\) 31\(\degree\).

Найти:

\(\angle\) \(BAD =\) [ ]\(\degree\);        \(\angle\) \(B =\) [ ]\(\degree\);

\(\angle\) \(BCD =\) [ ]\(\degree\);        \(\angle\) \(D =\) [ ]\(\degree\).