Дан фрагмент программы для формирования массива.
for i := 1 to 5 do A

:= i+2;
for i := 1 to 5 do writeln \('A⟨1⟩ = ', A⟨0⟩\);
Какой массив будет напечатан?

• A
  \[1\]
  = 3 A
  \[2\]
  = 4 A
  \[3\]
  = 5 A
  \[4\]
  = 6 A
  \[5\]
  = 7
• A
  \[1\]
  = 3 A
  \[2\]
  = 5 A
  \[3\]
  = 7 A
  \[4\]
  = 9 A
  \[5\]
  = 11
• A
  \[1\]
  = 1 A
  \[2\]
  = 2 A
  \[3\]
  = 3 A
  \[4\]
  = 4 A
  \[5\]
  = 5