Решите уравнение:
\(\cos(\frac{\pi}{3}-3x)=\frac{\sqrt3}{2}\)
\(\frac{\pi}{9}\pm\frac{\pi}{18}+\frac{2\pi n}{3},n\in Z\)
\(\frac{\pi}{6}+2\pi n,n\in Z\)
\(-\frac{\pi}{3}+2\pi n, n\in Z\)
\(\frac{\pi}{9}\pm\frac{\pi}{18}+2\pi n,n\in Z\)