Задание
\(\begin{cases} \text{3х+у=3 } \\ \text{3х+4у=-2} \end{cases}\)
- $x=1 \frac{2}{3};
y=1 \frac{5}{9}$ - $x=-1 \frac{2}{3};
y=1 \frac{5}{9}$ - $x=1 \frac{2}{3};
y=-1 \frac{5}{9}$ - $x=1,5556;
y=1,6667$