Задание
а) Реши уравнение:
| \(\log_{9}\) | \(\left(3^{2x} - 2\cos x - 4\sqrt{3}\sin^2 x\right) = x.\) |
|---|
- \(-\frac{\pi}{3} + 2\pi n, n \in \mathbb{Z}\)
- \(\frac{\pi}{3} + 2\pi n, n \in \mathbb{Z}\)
- \(\frac{5\pi}{6} + 2\pi n, n \in \mathbb{Z}\)
- \(-\frac{5\pi}{6} + 2\pi n, n \in \mathbb{Z}\)
- \(-\frac{2\pi}{3} + 2\pi n, n \in \mathbb{Z}\)
- \(\frac{\pi}{6} + 2\pi n, n \in \mathbb{Z}\)
- \(-\frac{\pi}{6} + 2\pi n, n \in \mathbb{Z}\)
- \(\frac{2\pi}{3} + 2\pi n, n \in \mathbb{Z}\)
б) Укажи все корни, принадлежащие отрезку \(\left[ \frac{17\pi}{2} ; 10\pi \right]\):
- \(\frac{53\pi}{6}\)
- \(\frac{28\pi}{3}\)
- \(\frac{26\pi}{3}\)
- другой ответ
- \(\frac{55\pi}{6}\)