а) 2\sin \dfrac{\pi}{12} \cos \dfrac{\pi}{12} = ; б) \left( \cos \dfrac{\pi}{8} -\sin \dfrac{\pi}{8}\right) \left( \cos \dfrac{\pi}{8} + \sin \dfrac{\pi}{8}\right)= .

Задание

Вычисли

а) \(2\sin \dfrac{\pi}{12} \cos \dfrac{\pi}{12} = \) [ ];

б) \(\left( \cos \dfrac{\pi}{8} -\sin \dfrac{\pi}{8}\right) \left( \cos \dfrac{\pi}{8} + \sin \dfrac{\pi}{8}\right)= \) [ ].