Задание
Реши уравнение
\(6\sin^2x-5\sin\left(\dfrac{3\pi}2+x\right)=2\)
- \(\pm\dfrac{\pi}3+2\pi n,\space n\in\mathbb{Z}\)
- \(\pm\dfrac{2\pi}3+2\pi n,\space n\in\mathbb{Z}\)
- \(\pm\dfrac{2\pi}3+3\pi n,\space n\in\mathbb{Z}\)
- \(\pm\dfrac{\pi}3+3\pi n,\space n\in\mathbb{Z}\)
Ответ:[ ]