1) x(x+2)=6+x-x^2; 2) 2x-x^2-\dfrac{2-x}{3}=0; 3) \dfrac{x(1-x)}{5}-\dfrac{1-x}{4}+\dfrac{x(x-1)}{10}=0.
Задание

Реши уравнения

  1. \(x(x+2)=6+x-x^2\) ;

  2. \(2x-x^2-\dfrac{2-x}{3}=0\) ;

  3. \(\dfrac{x(1-x)}{5}-\dfrac{1-x}{4}+\dfrac{x(x-1)}{10}=0\) .