9x^2- =(3x-1)( +1). \dfrac{4}{9}m^6- ^4=\bigg( \dfrac{2}{3}m^3- \bigg) \bigg( m^3+n^2\bigg).
Задание

Заполни пропуски

  1. \(9x^2-\) [ ] \(=(3x-1)(\) [ ] \(+1)\) .
  2. \(\dfrac{4}{9}m^6-\) [ ] \(^4=\bigg( \dfrac{2}{3}m^3-\) [ ] \(\bigg) \bigg( \) [ ] \(m^3+n^2\bigg) \) .